Scholar Tests · Sample paper
Secondary 4 Additional Mathematics, Paper 1
25 questions · 90 marks · 135 minutes · no negative marking
Name ______________________ Date ____________
Paper 1: multiple choice (calculator allowed)
Questions 1 to 10, 3 marks each. Circle the letter of the best answer.
- 1.
It is given that 2 cos x + 4 sin x can be written as R cos(x − α), where R > 0 and 0° < α < 90°. Find the value of R, correct to 3 significant figures.
- A20
- B4.47
- C3.46
- D6
- 2.
Find the coefficient of x4 in the expansion of (2 − 3x)7.
- A2835
- B−840
- C−20412
- D22680
- 3.
A particle moves in a straight line so that, t seconds after leaving a fixed point O, its velocity is v = 2t2 − 16t + 24 m/s. Find the displacement of the particle from O, in metres, when t = 2.
- A67/3
- B−64/3
- C0
- D64/3
- 4.
By completing the square, find the minimum value of y = x2 − 6x + 18.
- A27
- B9
- C−9
- D3
- 5.
Solve the equation 3 cos2 x − 16 cos x + 5 = 0 for 0° ≤ x ≤ 360°, giving each angle correct to 1 decimal place.
- Ax = 70.5°
- Bx = 109.5°, 250.5°
- Cx = 70.5°, 289.5°
- Dx = 19.5°, 160.5°
- 6.
Find the area of the region enclosed by the curve y = −x2 − 2x and the x-axis.
- A4
- B4/3
- C−4/3
- D8/3
- 7.
Find the range of values of k for which the equation 3x2 + kx + 12 = 0 has two distinct real roots.
- A−6 < k < 6
- Bk < −6 or k > 6
- Ck < −12 or k > 12
- D−12 < k < 12
- 8.
Expand and simplify (5 + 3√3)(5 − √3), giving your answer in the form a + b√3.
- A16 − 20√3
- B22 + 10√3
- C16 + 10√3
- D25 − 3√3
- 9.
An open box is made from a square sheet of card of side 12 cm by cutting a square of side x cm from each corner and folding up the sides. Find the greatest possible volume of the box, in cm³.
- A64
- B2
- C200
- D128
- 10.
ABCD is a parallelogram with A(2, −3), B(−2, 4) and C(0, −1). Find the coordinates of D.
- A(−4, 6)
- B(0, −8)
- C(4, −8)
- D(0, 2)
Paper 1: short answers
Questions 11 to 25, 4 marks each. Write your answer on the line.
- 11.
Each edge of a metal cube expands at a constant rate of 2 mm/s when it is heated. Find the rate, in mm³/s, at which its volume is increasing when each edge is 6 mm.
Answer: ______________
- 12.
A closed cylindrical can holds 800 cm³. Its total surface area is A = 2πr2 + 1600/r, where r cm is the radius. Find the least possible surface area, in cm², correct to 3 significant figures.
Answer: ______________
- 13.
The line y = x + 3 meets the curve y = x2 − 2x + 5 at the points A and B. Find the length of AB, correct to 3 significant figures.
Answer: ______________
- 14.
Solve the equation √(−x + 10) = x + 2.
Answer: ______________
- 15.
A curve has equation y = x3 − 9x2 + 2. Find the y-coordinate of the minimum point on the curve.
Answer: ______________
- 16.
A particle moves in a straight line so that, t seconds after leaving a fixed point O, its velocity is v = 3t2 − 9t + 6 m/s. Find the acceleration of the particle, in m/s², when t = 4.
Answer: ______________
- 17.
The curve y = −4 cos 2x − 3 is drawn for 0° ≤ x ≤ 360°. State the number of solutions of the equation −4 cos 2x − 3 = −4 for 0° ≤ x ≤ 360°.
Answer: ______________
- 18.
It is given that 4 cos x + 7 sin x can be written as R cos(x − α), where R > 0 and 0° < α < 90°. Find the value of α, correct to 1 decimal place. Give your answer in degrees.
Answer: ______________
- 19.
By completing the square, find the maximum value of y = −2x2 + 4x + 2.
Answer: ______________
- 20.
The variables x and y are related by y = ax2 + bx, where a and b are constants. When y/x is plotted against x, a straight line passes through the points (2, −1) and (7, −16). Find the value of a.
Answer: ______________
- 21.
Find the area of the region enclosed by the curve y = x2 − 7x + 6 and the x-axis.
Answer: ______________
- 22.
The population, P, of a town after t years is given by P = 33308e0.1t. Find the time taken for P to rise to 99924, correct to 3 significant figures. Give your answer in years.
Answer: ______________
- 23.
Solve the equation 2x − 1 = 45, giving your answer correct to 3 significant figures.
Answer: ______________
- 24.
Given that y = (−2x + 1)2, find the value of dy/dx when x = 0.
Answer: ______________
- 25.
The point P(1, 0) lies on the circle (x + 2)2 + (y + 4)2 = 25. The tangent to the circle at P meets the y-axis at Q. Find the y-coordinate of Q.
Answer: ______________
Answers and working
Paper 1: multiple choice (calculator allowed)
- 1.B (4.47). R = √(22 + 42) = √20. The answer is 4.47.
- 2.D (22680). The term in x4 is 7C4 × 23 × (−3x)4. 7C4 = 35, so the coefficient is 22680. The answer is 22680.
- 3.D (64/3). s = ∫v dt = (2/3)t3 − 8t2 + 24t, with s = 0 at t = 0. At t = 2, s = 64/3. The answer is 64/3.
- 4.B (9). x2 − 6x + 18 = (x − 3)2 + 9. The squared bracket is never negative, so y is least when x = 3, where y = 9. The answer is 9.
- 5.C (x = 70.5°, 289.5°). Factorise: (3 cos x − 1)(cos x − 5) = 0. cos x = 1/3, and cos x = 5 has no solution. The answer is x = 70.5°, 289.5°.
- 6.B (4/3). The curve meets the x-axis at x = −2 and x = 0. ∫ from −2 to 0 of (−x2 − 2x) dx = 4/3. Area = 4/3. The answer is 4/3.
- 7.C (k < −12 or k > 12). b2 − 4ac = k2 − 4 × 3 × 12 = k2 − 144. Two real roots needs k2 > 144, so k < −12 or k > 12. The answer is k < −12 or k > 12.
- 8.C (16 + 10√3). Multiply out: 25 − 5√3 + 15√3 − 3 × 3. Collect: 16 + 10√3. The answer is 16 + 10√3.
- 9.D (128). V = x(12 − 2x)2, so dV/dx = (12 − 2x)(12 − 6x). dV/dx = 0 at x = 2 (x = 6 gives no box), and d2V/dx2 < 0 there, a maximum. V = 2 × 82 = 128. The answer is 128.
- 10.C ((4, −8)). The diagonals of a parallelogram bisect each other, so AC and BD share a midpoint. D = A + C − B = (4, −8). The answer is (4, −8).
Paper 1: short answers
- 11.216. V = x3, so dV/dx = 3x2 = 108. dV/dt = 108 × 2 = 216. The answer is 216.
- 12.477. dA/dr = 4πr − 1600/r2 = 0 when r3 = 800/(2π), so r = 5.03. d2A/dr2 > 0 there, a minimum, and A = 477. The answer is 477.
- 13.1.41. Solving the two equations gives A(1, 4) and B(2, 5). AB = √(12 + (1)2) = 1.41. The answer is 1.41.
- 14.1. Square both sides: −x + 10 = (x + 2)2, which gives x = 1 or x = −6. Check each in the original: x = −6 makes the right side negative, so only x = 1 works. The answer is 1.
- 15.−106. dy/dx = 3x2 − 18x = 3x(x − 6), which is 0 at x = 0 and x = 6. d2y/dx2 = 6x − 18 is negative at x = 0 and positive at x = 6. So the maximum is at x = 0 and the minimum at x = 6, where y = −106. The answer is −106.
- 16.15. a = dv/dt = 6t − 9. At t = 4, a = 15. The answer is 15.
- 17.4. The curve runs from −7 to 1 with period 180°. The line y = −4 lies between them, so it crosses the curve twice in each full cycle: 4 times from 0° to 360°. The answer is 4.
- 18.60.3. R cos α = 4 and R sin α = 7, so tan α = 7/4. α = tan⁻¹(7/4) = 60.3°. The answer is 60.3°.
- 19.4. −2x2 + 4x + 2 = −2(x − 1)2 + 4. The squared bracket is never negative, and it is subtracted, so y is greatest when x = 1, where y = 4. The answer is 4.
- 20.−3. Divide through by x: y/x = ax + b, a straight line with gradient a and intercept b. Gradient = (−16 + 1) ÷ (7 − 2) = −3; then the intercept from either point. The answer is −3.
- 21.125/6. The curve meets the x-axis at x = 1 and x = 6. ∫ from 1 to 6 of (x2 − 7x + 6) dx = −125/6, negative because the region is below the axis. Area = 125/6. The answer is 125/6.
- 22.11.0. 99924 = 33308e0.1t, so e0.1t = 3.000. Take ln: 0.1t = ln 3.000, so t = 11.0. The answer is 11.0 years.
- 23.6.49. Take lg of both sides: (x − 1) lg 2 = lg 45. x = lg 45 ÷ lg 2 + 1 = 6.49. The answer is 6.49.
- 24.−4. By the chain rule, dy/dx = −4(−2x + 1). At x = 0, −2(0) + 1 = 1, so dy/dx = −4. The answer is −4.
- 25.3/4. The radius to P has gradient 4/3, so the tangent has gradient −3/4. The tangent is 3x + 4y = 3; put x = 0: y = 3/4. The answer is 3/4.
Written by Scholar Tests to SEAB's SEC G3 Additional Mathematics syllabus. Not a school paper. Scholar Tests is not connected with MOE, SEAB or any school.